Knots Versus Miles per Hour

Knots is how the speed of aircraft and boats is measured. Both miles per hour and knots is a speed which is the number of units of distance that is covered for a certain amount of time.

1 knot = 1 nautical mile per hour = 6076 feet per hour
1 mph =1 mile per hour = 5280 feet per hour

For example, if a train is moving at 50 mph on a track, how would you represent this speed in knots (even though trains are not usually represented in knots)?

To do this problem easily, one can multiply the number of miles per hour that the train is moving by the number of feet per hour that = 1 mph. this converts the speed to a distance traveled in one hour.
That is,

(50 mph)(5280 feet/ mph)=264,000 feet

Now, divide that distance by the number of feet in a nautical mile (6076).

(264,000 feet)/(6076 feet/ knot) = 43.4 knots

 

Exercises:

  1. Complete the following chart:

    2 knots = ? mph, ? knots = 10 mph, 58 knots = ? mph, ? knots = 64 mph,
 110 knots = ? mph, ? knots = 250 mph
    (answer)

In aerodynamics, speed is also measured by the Mach number, which is the ratio of the speed of the object to the speed of sound. Mach 1 means that you are traveling at the speed of sound or 661.7 knots, or

Mach 1 = 661.7 knots

How would you determine the speed of sound in mph?
Since

661.7 knots = (661.7 nautical miles/hr) (6076 feet/nautical miles)
= 4,020,489.2 feet/hr

and

(4020489.2 ft/hr)/(5280 ft/mile)=761.5 mph

We can say that Mach 1 = 761.5 mph at sea level.

Since the speed of sound varies with the density of air ( or whatever material it is transmitted through), one needs to determine the density of the air the aircraft is flying through. To compute this, we will use the chart shown below, called the International Civil Aviation Organization Table, or I.C.A.O.

Notice as the altitude increased, the density of air decreases as does the speed of sound in knots.

 

  1. Using the I.C.A.O. table below, complete the following chart:

    Find Mach 1 (knots) for alt = 2,000,  6,000, 15,000, 35,000, and 42,000 feet
    (answer)

     

  2. Now complete the following chart:

    A text only version of this problem and answer are also available.

    A table containing problem #3
    (answer)

     


I.C.A.O. Standard Atmosphere
Altitude
(Feet)
Density Speed of Sound
(Knots)

0

.002377

661.7

1,000

.002308

659.5

2,000

.002241

657.2

3,000

.002175

654.9

4,000

.002111

652.6

5,000

.002048

650.3

6,000

.001987

647.9

7,000

.001927

645.6

8,000

.001868

643.3

9,000

.001811

640.9

10,000

.001755

638.6

15,000

.001496

626.7

20,000

.001266

614.6

25,000

.001065

602.2

30,000

.000889

589.5

35,000

.000737

576.6

36,089 *

.000706

573.8

40,000

.000585

573.8

45,000

.000460

573.8

50,000

.000362

573.8

55,000

.000285

573.8

* Geopotential of Tropopause


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Created by Carol Hodanbosi
WWW pages edited by Jonathan G. Fairman - August 1996

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Curator:
Tom.Benson@grc.nasa.gov
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